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 规则解 在 计算机软件及计算机应用 分类中 的翻译结果: 查询用时：0.252秒
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 规则解
 rule-solution
 3. If the union of positive-examples set and negative-examples set equals to the space which consists of all examples, the rule-solution is unique. (3)若正例集与反例集之并等于全部例子构成的空间,则规则解唯一; 短句来源
 “规则解”译为未确定词的双语例句
 On the Solution for the System of Linear equationS by Flow Graph Reduction Rule 用流图简化规则解线性方程组 短句来源 2. There are no solutions when positive-examples set intersets negative-examples set. (2)正例集与反例集相交时,规则解不存在; 短句来源 In this paper we mainly discuss the properties of regular solution, the limit situation on 本文主要讨论Schrodinger方程: (△/2+q)u(x)=0的规则解的性质,在边界点上的极限行为,以及逆随机Dirichlet问题规则解的存在性。 得到了一系列新结果。 短句来源

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 equation
 For these polynomials we prove an integral representation, a combinatorial formula, Pieri rules, Cauchy identity, and we also show that they do not satisfy any rationalq-difference equation. The Yang-Baxter equation admits two classes of elliptic solutions, the vertex type and the face type. The inverse conductivity problem to the the elliptic equation ${\rm div}((1+(k-1)\chi_D)\nabla u)=0\ {\rm in }\ \Omega$ is considered. As applications, the wave equation on?+ × ?+ and the heat equation in a semi-infinite rod are considered in detail. Pointwise fourier inversion: A wave equation approach 更多
 equation
 For these polynomials we prove an integral representation, a combinatorial formula, Pieri rules, Cauchy identity, and we also show that they do not satisfy any rationalq-difference equation. The Yang-Baxter equation admits two classes of elliptic solutions, the vertex type and the face type. The inverse conductivity problem to the the elliptic equation ${\rm div}((1+(k-1)\chi_D)\nabla u)=0\ {\rm in }\ \Omega$ is considered. As applications, the wave equation on?+ × ?+ and the heat equation in a semi-infinite rod are considered in detail. Pointwise fourier inversion: A wave equation approach 更多
 In this paper, an initial study of learning from examples is made. After the rule-space of solutions is enlarged from normal formula solutions to all general formula solutions, the following conclusions are got:1. Discussing the change of corresponding rules set, with the change of examples set. 2. There are no solutions when positive-examples set intersets negative-examples set. 3. If the union of positive-examples set and negative-examples set equals to the space which consists of all examples, the rule-solution... In this paper, an initial study of learning from examples is made. After the rule-space of solutions is enlarged from normal formula solutions to all general formula solutions, the following conclusions are got:1. Discussing the change of corresponding rules set, with the change of examples set. 2. There are no solutions when positive-examples set intersets negative-examples set. 3. If the union of positive-examples set and negative-examples set equals to the space which consists of all examples, the rule-solution is unique. 4. If the solutions exist, there must be two basic solutions, and these two solutions are maximum and minimum, under the relation of partial-order "(?)". 5. The rule set for the operate V, A forms a bounded distributive lattice, and the two basic solutions are the upper bound and the lower bound of this lattice respectively. 6. GS theorem corresponding to GS algorithm is given. 本文对示例或学习的理论进行了初步的研究。首先,扩充了解的规则空间,由范式解扩充到任意公式解。然后,得到了如下结果:(1)讨论了随着例子集合的变化,相应规则解集合的变化情况;(2)正例集与反例集相交时,规则解不存在;(3)若正例集与反例集之并等于全部例子构成的空间,则规则解唯一;(4)在有解情况下,必然存在两个基础解,在半序关系“”下,这两个解分别为最小元,最大元。(5)规则集合关于运算∧,∨作成一个有界分配格。两个基础解是此格的上,下界。(6)对应于GS算法的GS定理。
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