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    The experimental results show that: the bigger the grain parameter is, the greater the expansion is and the longer the stabilization period is. The ideal grain parameter scope is 30-100μm and the grain with parameter less than 10μm should be no more than 20% when the grain parameter scope in 10-100μm.
    试验结果表明,颗粒越粗,膨胀越大,膨胀稳定期也越,理想拉径范围是30-100μm,当粒径范围在10- 100μm时,小于10μm的颗粒不应该多于20%。
    Discuss of cracking control technology on longer ferro-concrete wall of basement
    地下室钢筋混凝土墙裂缝控制技术的探讨
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    It indicates that compared with the response spectrums of no velocity pulse records, the response spectrums of velocity pulse records have longer maximum number range, as well as bigger numbers at long periods.
    结果表明在近断层的情况下,相对无速度脉冲记录,有速度脉冲记录反应谱的平台段较,在周期段,有速度脉冲的记录的反应谱值要比没有速度脉冲的反应谱值偏大;
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    The pile stiffness is reduced by the pile-pile interaction and the effective length of piles becomes longer.
    桩 桩相互作用降低了桩的刚度 ,并使群桩的有效桩加大了。
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    The greater the amplitude change of head wave of transverse velocity is, the severer the damage is, the later the arriving time of the first wave hollow and the longer the damaged element will be.
    当脉冲作用点在受损单元的起始位置时 ,脉冲作用点横向速度波首波波幅变化越大 ,损伤越大 ,脉冲作用点横向速度波的第一个波谷到达时间越晚 ,损伤单元越
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  延长
    Moreover, the longer the curing age, the higher the carbonation resistance of concrete.
    施加荷载后混凝土的抗碳化能力显著劣化,而延长养护龄期可提高混凝土的抗碳化能力.
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    Largeradsorption capacity is obtained with the longer contact-time.
    随接触时间的延长而增大。
短句来源
    A small cushion clearance with a adequate cushion length can apparently reduce the piston’s bumping speed, while it can’t more apparently reduce the piston’s bumping speed with longer cushion length but extend the shift time.
    当缓冲间隙很小时,适当的缓冲长度就可以明显地降低顶缸速度,但缓冲长度超出一定值时,并不能进一步明显降低顶缸速度,只会使换向时间明显地延长
短句来源
    The test results show that RC beams strengthened by HSSWM have longer fatigue life.
    疲劳试验结果表明:在疲劳荷载作用下,加固层和本体梁能较好地共同参与受力,从而提高构件的承载能力,延长疲劳寿命;
短句来源
    Now, because of scarcity of the total electric supply and the mismatch of peak and off-peak load, the electric power becomes new trend that the peak load time lasts longer and the off-peak load time get shorter, thus the original direct evaporate ice-on-coil device is not suit to the change of the electric power, so it is necessary to study the coil direct evaporate ice-on-coil device again.
    目前,在总供电量明显不足,电网负荷依然存在较大峰谷差的情况下,电网负荷又产生了新的变换趋势,高峰负荷时段逐渐延长,低谷负荷时间缩短,原有的直接蒸发蓄冰装置已不能适应电网负荷的变化趋势。
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  较长
    It indicates that compared with the response spectrums of no velocity pulse records, the response spectrums of velocity pulse records have longer maximum number range, as well as bigger numbers at long periods.
    结果表明在近断层的情况下,相对无速度脉冲记录,有速度脉冲记录反应谱的平台段较长,在长周期段,有速度脉冲的记录的反应谱值要比没有速度脉冲的反应谱值偏大;
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    The experimental results showed that the effluent turbidity was stable at 0.2~0.5 NTU and its removal efficiency was more than 90%. The removal efficiency of COD_(Mn) and that of UV_(254) were about 50~65% and 33~65%,respectively. The period of membrane was longer so that it could operate about 60~70 hours.
    结果试验结果表明,该工艺对浊度的去除率在90%以上,出水浊度在0.2~0.5 NTU,对CODMn和UV254的去除率分别可达50%~65%和33%~65%,组合工艺中膜过滤周期较长,可达60~70 h.
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    Taking a bath 15 minutes every time per day, if you want a better result, longer time spend in maintaining the health recovery is necessary, half month to a month in general.
    洗浴温矿泉每天每次15分钟,要起到良好的疗养效果,应进行较长时日的保健疗养,一般半个月到一个月。
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    The dog-bone steel flange can protect the welds, meanwhile it will be able to result in a longer plastic zone formed in the flange, thus providing greater ductile deformation and more excellent energy dissipation capacity.
    钢梁翼缘削弱能有效的保护焊缝,还能在削弱部位形成较长的塑性区,因此狗骨式节点具有更大的延性和更好的耗能能力。
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    Sedimentation of soft soil groundwork in this area has the features of bigger transformation, serious uneven sedimentation and longer stable sedimentary period, and also more influences from geology and climate.
    东北地区的软土地基沉降除了具有变形大、不均匀沉降大、沉降稳定历时较长的特点外,受地质和气候因素影响也较大,这极大地影响了道路的长期稳定和安全使用,使得东北地区道路建设的难度加大。
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  延长
    Moreover, the longer the curing age, the higher the carbonation resistance of concrete.
    施加荷载后混凝土的抗碳化能力显著劣化,而延长养护龄期可提高混凝土的抗碳化能力.
短句来源
    Largeradsorption capacity is obtained with the longer contact-time.
    随接触时间的延长而增大。
短句来源
    A small cushion clearance with a adequate cushion length can apparently reduce the piston’s bumping speed, while it can’t more apparently reduce the piston’s bumping speed with longer cushion length but extend the shift time.
    当缓冲间隙很小时,适当的缓冲长度就可以明显地降低顶缸速度,但缓冲长度超出一定值时,并不能进一步明显降低顶缸速度,只会使换向时间明显地延长
短句来源
    The test results show that RC beams strengthened by HSSWM have longer fatigue life.
    疲劳试验结果表明:在疲劳荷载作用下,加固层和本体梁能较好地共同参与受力,从而提高构件的承载能力,延长疲劳寿命;
短句来源
    Now, because of scarcity of the total electric supply and the mismatch of peak and off-peak load, the electric power becomes new trend that the peak load time lasts longer and the off-peak load time get shorter, thus the original direct evaporate ice-on-coil device is not suit to the change of the electric power, so it is necessary to study the coil direct evaporate ice-on-coil device again.
    目前,在总供电量明显不足,电网负荷依然存在较大峰谷差的情况下,电网负荷又产生了新的变换趋势,高峰负荷时段逐渐延长,低谷负荷时间缩短,原有的直接蒸发蓄冰装置已不能适应电网负荷的变化趋势。
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  longer
In general, such a tensor product is no longer irreducible.
      
Overall the pharmacokinetic properties of both isomers were similar in rats, monkeys and humans, with β-isomer exhibiting longer elimination half-life, MRT, volume of distribution and clearance, irrespective of the route of administration.
      
This means that the resistance calculation based on two-dimensional models can no longer provide sufficiently accurate results.
      
It is also discovered that the major approaches to artificial intelligence in history, the structuralism, functionalism and behaviorism, can harmoniously be unified within the framework of the mechanism approach and no longer be contradictory.
      
euphratica leaves exhibited a higher capacity to exclude salt in a longer period of increasing salinity, thus limited salt-induced lipid peroxide and MP, which contributed to membrane integrity maintenance and salt tolerance of P.
      
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Two methods for analyzing caisson-beams are introduced in this paper.One is the well-known method of redundant forces. The author has simplified this methed by using couples of redundant forces to set up a typical equation and pointing out the rule that the matrix of the coefficients of simultaneous linear equations which are organized from the expansion of that typical equation. This method can be easily solvd when the number of unknown redundant forces, or that of equations, is less than 3 or 4; but it will...

Two methods for analyzing caisson-beams are introduced in this paper.One is the well-known method of redundant forces. The author has simplified this methed by using couples of redundant forces to set up a typical equation and pointing out the rule that the matrix of the coefficients of simultaneous linear equations which are organized from the expansion of that typical equation. This method can be easily solvd when the number of unknown redundant forces, or that of equations, is less than 3 or 4; but it will be difficult when the number is more than that. In order to solve this difficulty the author suggests another kind of method of which the essential principle is mentioned in the following.Supposing that the distance between the beams is sufficiently short in comparing with their spans, we can set up a partial differential equation for its deffiection W, as we often do in the theory of elasticity. In this way we can solve it with its boundary conditions of simple supporting by sine series. From this we can easily get the formulas of bending moments, shears and twist moments of each beam by partially differentiating the function of deffiection. The result of the calculation proves that it quite agrees with the method of redundant forces when the distance between beams is no longer than 1/5 of their spans.There are some tables given in this raper for practical use.

本文介紹了計算井字梁的兩种方法。 第一种方法是按冗力送来計算的。本文利用了成对的未知力以建立冗力法的典型方程,指明了由典型方程所組成的联立方程中其系数排列的規律,从而簡化了建立方程的过程和減少錯誤的机会。冗力法仅在联立方程的数目不多于3至4时是相当方便的,若未知冗力过多,解算过程便異常繁重。为此,笔者提出了下述的第二种方法。 当梁的間距比梁的跨度为一較小的数值时,可应用彈性力学所常用的方法,建立一个关于井字梁撓度曲面的偏微分方程。以符合簡支边界条件的正弦级数求出撓度后,便可依微分关系求出各梁的弯矩、切力及扭矩。鈇摩辛柯在其著作中(見[3]§37)討論向異性板的弯曲时,亦曾附帶地提及本法的可能性。本文給出了全部計算公式及为实用的目的而制訂了各种数表。計算的結果表明当梁間距不大于跨度的1/5时,本法与冗力法的結果相差無几,而本法在应用上的簡便笑为任何方法所不及。

This paper describe the analysis of stresses in a building of three spins and thre storeys. For the want of a better hame, we shall call the product of the sum of the shears at the either ends of eads tier of columns and their length the shear moment for that tier or storey. Evidently the sum of moments at ends of all the columns belonging tothe same storey must equal to the shear moment of the same storey. To begin with we assume that the shear moment in each storey separately equals l. Let us take the nth....

This paper describe the analysis of stresses in a building of three spins and thre storeys. For the want of a better hame, we shall call the product of the sum of the shears at the either ends of eads tier of columns and their length the shear moment for that tier or storey. Evidently the sum of moments at ends of all the columns belonging tothe same storey must equal to the shear moment of the same storey. To begin with we assume that the shear moment in each storey separately equals l. Let us take the nth. storey first. A unit shear moment in this storey will induce certain fixed-end moments in the columas, which will be then distributed among the joints at end of the columns belonging to this storey_2 leaving the moments at any other joint alone. Since the block distribution coefficients and carrying over factors to the second joints used for this distribution are calculated for the whole truss, the moments in a number of joints are still unbalanced, at the same time new moments appear at ends of columns of the (n+1) th and(n—l) th. storeys, so that new shear moments are acquired also by these two storeys. On the other hand the shear moment in the nth. storey is no longer equals to 1, but some new value a. this will not matter, the important thing is that we have determined definitely the ratios between this uew shear moment value a and the moments at the ends of the columns belonging to these three storeys and the shear moments in storeys below and above, In order to bring the value of the shear moment in the nth. storey back to l, we divide all these end moments and shear moments by a, the result is a set of new values, which will be called, for convenience, the influence values due to shear moment in the nth. storev.Wben the building truss is being analysed, we multiply the influence values of different storeys by a set of suitable numbers, and put the results in successive rows in a table. The multiplying should be so chosen that the sums of shear moments for saeh storey should equal approximately their actual values. The end moments are then balanced by block distribution. After this distribution the shear moment for each storey will differ from their actual values appreciably7 the difference wiil be then made up by repetition of the above process as'often as required. For the truss under consideration7 the calculations are repeated only once, then the maximum error in values of shear moments is already so low (only 0.075%), a second repetition of the process is quite unnecessary.

本文計算的是一个三層三间的屋架?衙繉拥淖∽拥淖芗袅退麄兊母叨鹊某朔e喚做这一層的剪力矩,那么这个剪力矩是和同一層的柱子的两端的弯矩的总和值相等的燃俣恳粚拥募袅氐扔?.为便利超見,譬如我們先假定第n層的剪力矩等于1。把这一層的各柱子的兩端的固定端弯炬求得,再把他們在本層的柱子的兩端的各結点分配一下。因为我們用的集体分配系数和隔点傳遞系数是根据整个屋架計算的緣故,有一部分的結点的弯矩是不完全平衡的,同时第n—1和n+1層的柱子的两端出现了新的弯炬,因此这两層也出現了新的剪力矩了。在另一方面,第n層的剪力矩已經不等于1,却等于一个新值α了。但是本層和上下两層的柱子两端的弯矩和上下两層的剪力矩和这个新剪力矩值α的中間是有一定的比例的。为了要本層的剪力矩值仍旧变成1,我們拿α除所有弯矩值和剪力矩值,因此我求得一系列的新值,这些新值就喚做n層的剪力矩的影响值嬎阄菁苁蔽覀兡檬实钡氖党烁鲗拥募袅氐挠跋熘?叫各厨的剪力矩的总和差不多和他們的实在值相等,然后進行分配弯矩。分配之后,各層的剪力矩和他們的实在值必定还有一定的距离或一定的差数。因此我們再用另一批适当的新数值乘各層的剪力矩的影响值,叫各層的剪力矩的总和差不...

本文計算的是一个三層三间的屋架?衙繉拥淖∽拥淖芗袅退麄兊母叨鹊某朔e喚做这一層的剪力矩,那么这个剪力矩是和同一層的柱子的两端的弯矩的总和值相等的燃俣恳粚拥募袅氐扔?.为便利超見,譬如我們先假定第n層的剪力矩等于1。把这一層的各柱子的兩端的固定端弯炬求得,再把他們在本層的柱子的兩端的各結点分配一下。因为我們用的集体分配系数和隔点傳遞系数是根据整个屋架計算的緣故,有一部分的結点的弯矩是不完全平衡的,同时第n—1和n+1層的柱子的两端出现了新的弯炬,因此这两層也出現了新的剪力矩了。在另一方面,第n層的剪力矩已經不等于1,却等于一个新值α了。但是本層和上下两層的柱子两端的弯矩和上下两層的剪力矩和这个新剪力矩值α的中間是有一定的比例的。为了要本層的剪力矩值仍旧变成1,我們拿α除所有弯矩值和剪力矩值,因此我求得一系列的新值,这些新值就喚做n層的剪力矩的影响值嬎阄菁苁蔽覀兡檬实钡氖党烁鲗拥募袅氐挠跋熘?叫各厨的剪力矩的总和差不多和他們的实在值相等,然后進行分配弯矩。分配之后,各層的剪力矩和他們的实在值必定还有一定的距离或一定的差数。因此我們再用另一批适当的新数值乘各層的剪力矩的影响值,叫各層的剪力矩的总和差不多和这些差数相等,然后分配弯矩。这样一遍一遍的算下去等到求得剪力矩和他們的实在值中间没有差数或相差很小才歇手。我們計算这个例題时僅僅算了两遍,最大誤差已經小到0.075%,因此就沒有再算下去了。

Hydration of high alumina cements made by sintering process in rotary kiln is investiga-ted. Under 20℃ curing, the main hydration products of all of the three kinds of cements with successive higher CaO/Al_2O_3 ratios are CAH-(10) (not C_2AH_8) and alumina gel, i. e., they are essentially the same as the hydration products of the cement made by fusion process as generally reported. The hydration products of cement having a lower CaO/Al-2O_3 ratio or a higher CA_2 content are more stable.The formation of more...

Hydration of high alumina cements made by sintering process in rotary kiln is investiga-ted. Under 20℃ curing, the main hydration products of all of the three kinds of cements with successive higher CaO/Al_2O_3 ratios are CAH-(10) (not C_2AH_8) and alumina gel, i. e., they are essentially the same as the hydration products of the cement made by fusion process as generally reported. The hydration products of cement having a lower CaO/Al-2O_3 ratio or a higher CA_2 content are more stable.The formation of more basic hydrated aluminates (i. e., C_2AH_8 or C_3AH_6) and gibbsite of this kind of cement occurs at a higher curing tempera-ture.While the latter subjects to the same curing temperature as the cement of higher CaO/Al_2O_3,its initial products will be stable unless it subjects to a longer curing.Under various curing tempe-ratures, the variation of strength of the three cements can be explained by the difference in stability of the hydration products, cement of higher CaO/Al_2O_3 ratio providing the lowest thermal stability of the hydrated products and decreasing in strength of the paste under higher temperature.

研究了三种CaO/Al_2O_3不同的矾土水泥的水化,常温下的主要水化产物都是CAH_(10)(而不是C_2AH_3)和氧化铝胶滞体,与熔融法制矾土水泥是一致的。CaO/Al_2O_3小的水泥具有较好的稳定性,表现在生成或转化为高碱性水化铝酸钙(C_2AH_3或C_3AH_6)和三水矾土(AH_3)的温度较高;在同一养护温度下,水化物转化需要的时间亦较长,三种水泥在不同养护条件下的强度变化规律可从其水化产物的稳定性得到说明,即CaO/Al_2O_3比大的水泥生成的水化物热稳定性最差,高温下强度降低更甚。

 
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