全文文献 工具书 数字 学术定义 翻译助手 学术趋势 更多

 a random variable 在 数学 分类中 的翻译结果: 查询用时：0.069秒
 历史查询

 a random variable 随机变量(58)
 随机变量
 A Laplace inverse transformation of a random variable sequence of independent same exponential distribution 独立同指数分布的随机变量序列的一个Laplace反演变换 短句来源 Records about a Random Variable Distribution Function Definition Note 关于随机变量分布函数定义的一点注记 短句来源 The statistic properties of a random variable sequence on Z_9 gained by two random variable sequences on Z_3 由域Z_3上随机变量序列构造的剩余类环Z_9上随机变量序列的统计性质分析 Each input is modeled by a random variable. 网络的每一个输入分量由一个随机变量描述。 短句来源 eLet X be a random variable with exponential distribution whose density function is(?) 设 X 是具有指数分布的随机变量,其密度函数为p(x)=(?) 短句来源 更多
 “a random variable”译为未确定词的双语例句
 Study on Accelerated Factor and Conditionfor Constant Failure Mechanism(Ⅰ)—The Case for Lifetime is a Random Variable 论加速系数与失效机理不变的条件(Ⅰ)─—寿命型随机变量的情况 短句来源 Give the Distribution Function of a Random Variable Utilizing its Moments 随机变量的分布函数及其计算 短句来源 Polynomial Approximation of A Random Variable 随机变量的多项式最佳均方误差逼近 短句来源 Let X_(1,n),…, X_(N,n) be a segment of an infinite sequence of exchangeable random variables, X_(1,n)~*≤…≤X_(N,n)~* be its order statistics, and N=N(n) be a random variable which is independently distributed of the X＇s, n=1, 2,…. 设X_(1,n) …,X_(N,n)是可换r. V. 无穷序列的一段,X_(1,n)~＊≤…≤X_(N,n)~＊为其顺序统计量,N=N(n)是与这些X(1,N)独立的正整值r. 短句来源 A Method of Solving the Special Functional Equation Including a Random Variable and a Process of Deriving Constant Risk-Averse Utility Function 一种随机特殊函数方程的解法及定常风险厌恶效用函数的导出 短句来源 更多

我想查看译文中含有：的双语例句

 a random variable
 The duration of every job is a random variable distributed by a given law. The developed methods are based on the modified normal distribution function of a random variable. The amount of work required for servicing an incoming customer (workload) is a random variable with an arbitrary distribution function. The excess 1/f noise in a random lattice with bond resistances r～exp(-λx), where x is a random variable and λ?1, is studied theoretically. The zero temperature phase diagram for ultracold bosons in a random 1D potential is obtained through a site decoupling mean-field scheme performed over a Bose-Hubbard (BH) Hamiltonian, whose hopping term is considered as a random variable. 更多
 eLet X be a random variable with exponential distribution whose density function is(?) where-∞<μ<∞,O<σ<+∞,bothh and σ being unknown.This paper gives a new estimator of σ.(?)_2=(?)where (?)n is the sample size,r is the number of terms retained when censored on the right,and x_((j)) denotes the i-th order statistic,i=1,…,r.In this paper it is shown that for loss function L((?),or) =((?)-1) ~2,the risk of (?)_2 is much smaller than that of the best affine invariant estimation (?)_1=1/r(?); hence an improvement.... eLet X be a random variable with exponential distribution whose density function is(?) where-∞<μ<∞,O<σ<+∞,bothh and σ being unknown.This paper gives a new estimator of σ.(?)_2=(?)where (?)n is the sample size,r is the number of terms retained when censored on the right,and x_((j)) denotes the i-th order statistic,i=1,…,r.In this paper it is shown that for loss function L((?),or) =((?)-1) ~2,the risk of (?)_2 is much smaller than that of the best affine invariant estimation (?)_1=1/r(?); hence an improvement. 设 X 是具有指数分布的随机变量,其密度函数为p(x)=(?)其中-∞<μ<+∞,0<σ<+∞,μ和σ均未知。本文给出了σ的一个新的估计(?)+(n-r)x_((r))-nx_((1) )]·f(?)(y),此处y=(?),f(?)(y)=(?)n 是子样容量,r 是截尾数,x_((i))表示第 i 个顺序统计量(i=1,2,…,r)。文中证明了(?)关于损失函数 L((?),σ)=(((?)/σ)-1) ~2比最佳仿射同变估计(?)=1/r[(?)x_((i))+(n-r)x_((r))-nx_((1) )]处处有较小的风险,因此是一个改进。 According to the firsthand information collected in the past years, this papershows that the market requirement is a random variable with normal distributionand that there is a linear relation beTween the market requirement and the timewhich are obfained by regresssion analysis and the square error analysis and givesan algorithm to find the linear function for the final decision. 本文从过去几年的原始资料入手,用数理统计的方法证明市场需求量服从正态分布;用回归和方差分析的方法,找出社会需求量的函数关系,并在对市场需求进行科学予测找出需求量为线性函数的基础上,提出用手算法及电子计算机计算法找出社会需求量为常数或为线性函数的最佳方案的方法,从而进行最后决策。 Let X be a random variable with exponential distribution whose function is ?? where -∞<μ<∞, 00 is known, is inadmissible. 设X是具有指数分布的随机变量,其密度函数为?? 其中-∞<μ<∞,σ>0,均未知.本文考虑分位点θ=μ+ησ的估计问题,其中η>0,已知.本文证明了.在平方损失函数下,当η>n+2+1/n时(n是子样容量),θ的最佳仿射同变估计是不容许的,存在一个估计比它有一致较小的风险. << 更多相关文摘
 相关查询

 CNKI小工具 在英文学术搜索中查有关a random variable的内容 在知识搜索中查有关a random variable的内容 在数字搜索中查有关a random variable的内容 在概念知识元中查有关a random variable的内容 在学术趋势中查有关a random variable的内容
 CNKI主页 |  设CNKI翻译助手为主页 | 收藏CNKI翻译助手 | 广告服务 | 英文学术搜索
2008 CNKI－中国知网

2008中国知网(cnki) 中国学术期刊(光盘版)电子杂志社